math help

Test Preparation SAT Preparation
1

<p>CB blue book
pg 684 q 16. Little help?</p>

2

<p>[x] is defined as [x]=x^2 - x</p>

<p>So:
[a] = [a-2]
a^2 - a = (a-2)^2 - (a-2)
a^2 - a = a^2 - 4a + 4 - a + 2
4a = 6
a = 6/4 = 3/2</p>