Math help

<p>I am stuck in the 620-640 range..</p>

<p>On the first math section with the 20 mult. choice, I do fine and get only around 2 wrong.
On the second section, I can get all the multiple choice correct usually (the 8 questions), but with the free-response, I can only get around 6/10 - 7/10 correct..
On the last section with 16 q's, I almost always get the last 4 incorrect..</p>

<p>Any help??
I have gruber's complete sat guide... (not the math workbook though)..</p>

<p>Also, I need help with this question:</p>

<p>From a jar containing 50 pieces of candy, of which 25 are red and 25 are green, Ari has taken 3 red and 4 green pieces. He takes an additional 13 pieces from the jar. What is the least number of these additional pieces that must be red in order for Ari to have more red candies than green candies among all the pieces he has taken?</p>

<p>Answer is 8</p>

<p>25 red + 25 green = 50</p>

<p>-3 red and -4 green = 43 candies left.</p>

<p>22 reds + 21 greens leftover = 43</p>

<p>-13 = 30 left in the jar.</p>

<p>Altogether, he has taken 20 pieces of candy.</p>

<p>3 reds</p>

<p>4 greens</p>

<p>7 + 6 = 13 </p>

<p>1) 3 reds + 7 = 10
2) 4 greens + 6 = 10</p>

<p>So 7 & 6 is can’t work because red has to be more than green.</p>

<p>8 + 5 = 13</p>

<p>1) 8 + 3 = 11
2) 4 + 5 = 9</p>

<p>11 reds and 9 greens. Answer is 8.</p>