<p>Blue Book Test # 4</p>
<p>Section 6 question 16</p>
<p>Let The function h be defined by h(x)=14+x^2/4
If h(2m)=9m, what is one possible value of m?</p>
<p>m can be either 7 or 2.</p>
<p>This is how I solved it:
h is defined by the function of h(x).
h (2m) = 9m
Plugging into the function of h (x)
h(2m) also = 14 +(4m^2)/4</p>
<p>Since obviously h(2m)=h(2m),
we can substitute for:
9m = 14 +(4m^2)/4
Multiply both sides by 4,
36m = 56 + 4m^2
Subtract 36m from both sides and Rearrange,
4m^2 - 36m + 56 = 0
Simplify:
m^2-9m+14 = 0
This is a quadratic equation.</p>
<p>You can factor it to become:
(m-7)(m-2) = 0
or you can use the quadratic formula.</p>
<p>Either way, m = 2, 7</p>
<p>h(x)=14+x^2/4
If h(2m)=9m; Find m</p>
<p>14+4m^2/4=9m
14+m^2=9m
m^2-9m+14=0
(m-7)(m-2)=0</p>
<p>m=2,7</p>
<p>oh wow thank you guys i was stupid and didnt square the 2 in 2m thank you again</p>
<p>^ETS always tries to trick us by doing stuff like that. Watch out for squaring!</p>