<p>How would you solve this problem?
<a href="http://i56.tinypic.com/mieyhs.jpg%5B/url%5D">http://i56.tinypic.com/mieyhs.jpg</a></p>
<p>Got got (E) sqrt2/2</p>
<p>It looks really intimidating at first, but I found that if you can find a way to break up there tough circle problems into squares you should be fine.</p>
<p>First I decided to only work on 1/4 of the total square.
I saw that the box’s side is equal to 4 since the radius of the large circle is 1 (diameter 2)
Next I broke down the quarter square (one circle + 1/4 the small circle) into a 45/45 right triangle.
Since each leg equals 2 (1/2 of the edge, which is 4) the hypotenuse equals 2sqrt2.</p>
<p>Now you can see that the diameter of the large circle is 2, so I subtracted that from the hypotenuse.</p>
<p>I was left with sqrt2, and after careful examination, I could see that the spaces outside the large circle were equal.</p>
<p>So all I needed to do was divide by 2 and get my radius.</p>
<p>It looks like a lot of steps, but it only took about 30 seconds to do. I hope that helps.</p>
<p>Thanks, I just don’t get the end of your explanation. Can someone else explain?</p>
<p>How would you solve this problem?</p>
<p>Hint: Attempt to calculate the value of the distance between the center of one of the large circles and the center of the small one. One way is to build a triangle with two legs of 1. </p>
<p>After obtaining that value, you can deduct the value of the radius of one large circle, namely deduict 1. </p>
<p>By the way, could there be answer that includes … something minus 1? :)</p>
<p>PS You could also use the starting point of the solution posted above. Of course, only to the point where the distance between the center of one of the large circles and the center of the small one half of … 2sqrt2.</p>
<p>Thanks for the tip! Made it so much easier! Is the correct answer D?</p>
<p>Yes, I got D.</p>