<p>imgur:</a> Math II Question Can anybody explain the most efficient way to do this and if there is a way to just do it on the calculator?</p>
<p>nvm, solution found!: [Sequences</a> Using the Graphing Calculator](<a href=“http://mathbits.com/mathbits/tisection/Algebra2/sequences.htm]Sequences”>http://mathbits.com/mathbits/tisection/Algebra2/sequences.htm)</p>
<p>Honestly, you might be better off just doing that one by hand; gives you the recursive formula; all you have to do is add up the previous two terms to get the next one:</p>
<p>n=1 1 (given)
n=2 1 (given)
n=3 2 (1+1)
n=4 3 (1+2)
n=5 5 (2+3)
n=6 8 (3+5)
n=7 13 (5+8)
n=8 21 (8+13)
n=9 34 (13+21)
n=10 55 (21+34)</p>
<p>And they ask for the 10th term, so n=10 which is 55 is your answer.</p>
<p>Well in the event that they would ask for like the 33rd term, I like to be prepared.</p>