<p>A sum of $10,000 is invested at a rate of 10 percent, with interest compounded semiannually. The value, in dollars, of this investment after t years is given by V(t)=10,000(1.05)^2t. Approximately how much greater is the value of this investment at the end of 2 years than the same amount invested at the rate of 10 percent compounded annually?</p>
<p>The answer is $55. I thought all I had to do was plug 2 into that equation and half the product to find the answer, but I'm apparently wrong. Can someone explain how to do this?</p>