math IIC help

<p>I took it a few months ago and only got a 680, which was not where I wanted to be at all. I think I'm a fairly good math student, but my school doesn't teach as in depth as many other schools. I need to up my score preferably to 750+, but at this point, anything better than 680 will be an improvement. Any suggestions on increasing my score?</p>

<p>Right now I have no math class, so it isn't so fresh in my mind. I bought the Barron's book, and looking at it makes me think I was lucky to get a 680 the first time. Anyone else improve a lot and can provide some encouragement? It is hard to motivate yourself to spend your time learning from a book because you haven't learned all the lessons in school.</p>

<p>The Barron's IIC book is notorious for being harder than the actual test. Study the Barron's.. along with your school studies, and you'll do fine.</p>

<p>is there a SAT I math section book that has only the hard problems? im wastin my time with 4/5 of the princeton review book.</p>

<p>You could always try Kaplan's SAT 1600 which claims to be harder.</p>

<p>Can someone explain how to solve this problem</p>

<p>In how many ways can 10 people be divided into two groups, one with 7 people and the other with 3 people?</p>

<p>the answer was 120</p>

<p>everzinny, I'm not very good at explaining, but I'll give it a shot. </p>

<p>If you've ever learned anything about that xCy key on your calculator, here's when you use it, because out of 10 people, you want a group of 7 (or 3, but it's the same thing pretty much because that's what's left over) and you don't care which order it is, so you just put in 10 C 7 in your calculator and you get 120.</p>

<p>To do it mathematically, it's
10! / (7!3!)
which means
(10<em>9</em>8<em>7</em>6<em>5</em>4<em>3</em>2<em>1) / (7</em>6<em>5</em>4<em>3</em>2<em>1)(3</em>2<em>1)
But since 7! is in 10!, you can simplify it out to
(10</em>9<em>8) / (3</em>2*1)
which equals 720/6 = 120.</p>

<p>I hope I didn't confuse you that much!</p>

<p>10 choose 3 is the same as 10 choose 7, so either way youll get 120. i learned how to do that method THIS YEAR, in an advanced pre-calculus class (analytical geometry/calcus). because pre-calc isnt part of the new sat, im guessing they expect you to solve it the way crazy14 showed you, with 10!/(7!3!)</p>

<p>Permutations and combinations are explained well in the Barron's IIC book.</p>

<p>I learned about the C and P stuff in my trig class.. except it was called Trigonometry/Discrete so I guess it was part of the discrete part because isn't it like statistics and stuff?</p>