Math IIC in Real SAT II, (don't look if you are going to take it)

Test Preparation
1

<p>I did really well on the test, but the only problem I couldn't get was the first one, I thought they were supposed to be the easiest. Accordding to the chart 79% of kids got it right but I still don't get it.</p>

<p>If 1 - (1/x) = 3 - (3/x) , then 1 - (1/x) =</p>

<p>A. -.5
B. 0
C. .5
D 2/3
E 3</p>

<p>The answer is 0, why?
Thanks</p>

2

<p>are you thinking that x=0? That's is what I thought at first...but the question is the equation, not what x equals. So x=1, therefore, the equation equals 0. I think...</p>

3

<p>1-(1/x) = 3-(3/x)
1= 3-(3/x)+(1/x)
1-3= -(3/x)+(1/x)
-2=(-2/x) (divide both sides by -2)
1=1/x
x=1</p>

<p>Replace x=1 into the equation 1-(1/x)
= 1-(1/1)
=1-1
= 0</p>

4

<p>yup see above</p>

5

<p>Lol, it's basic algebra..even I understand it:P</p>

6

<p>Ha...I remember this question from a day ago. Its in the Real Sat II's collegeboard book right?</p>

7

<p>Yes its from the book. I guess I completely misread the question. Thanks for your promt response, I can't believe out of all of them I get one of the simplest ones wrong.</p>

8

<p>It's easier just to substitute y = 1- (1/x).</p>

<p>Then your equation is y=3y, and y obviously equals 0.</p>