<p>^Wow try not being lazy. Just do it and stop complaining. And no it does not take long</p>
<p>And there are NO Polar graphs or any of that stuff on the test.</p>
<p>^ I've been curious about that for awhile. How do you graph something that isn't in the form y(x) = ?</p>
<p>Polar graphs aren't that bad, actually.</p>
<p>God, I lovvvve my precalc teacher for making us do all that weird stuff like parametric equations and everything!</p>
<p>you have to solve for y to graph that.</p>
<p>Oh pretend you have Ax2 + Cy2 + Dx + ey + f = 0</p>
<p>You wont have a B term on this test so..</p>
<p>If you really wanted to.. we had to do this in class... not fun</p>
<p>A(x2 + Dx/A + (Dx/2a)^2 ) + C (Y2 + Ey/C + (Ey/2a)^2) = -F + (Dx/2a)^2*a + (Ey/2a)^2 * c</p>
<p>Now to shorten it
A (X + (dx/2A))^2 + C (Y + (Ey/2C)^2 = All that other stuff I am too lazy to write down again.</p>
<p>We had to go further in my pre-calc class... now imagine if they had this on the Test @_@</p>
<p>pearfire, its just completing the square and substracting out the extraneous constants.</p>
<p>To graph polar, go to mode --> polar, same for parametric, only choose parametric.</p>
<p>If you wanna convert a polar equation to rectangular, remember that rcosX = x and rsinx = y</p>
<p>To convert from para. to rect., treat the x parameter as x and y parameter as y.</p>
<p>So there's no easy way to type in the equation of say, a circle, and have it graph it?</p>
<p>well... I'm not being lazy, I'm just trying to get an 800, and some guy on this forum stated that he had sooooo many programs for the math II test and therefore scored an 800</p>
<p>Don't worry, knowing Trig is all that's needed and also knowing your calculator like the back of your hand :) USE IT AS MUCH AS POSSIBLE...on most questions, use your calc...it'll save SO MUCH time and you'll need the time</p>
<p>Barron's is harder than the real thing :)</p>
<p>I know...a lot of ppl were telling me the calculator takes away your time, but for the IIC, I believe if you aren't using it for like every question, then you're not saving time or doing it correctly.</p>
<p>hm... ur saying trig, huh? any good formulas for trig, or general advice for trig questions? i think the barrons tests just really confuse, and over prepare, as usual... i'll take the official test on wednesday, ^^</p>
<p>don't use ur calculator as much as possible. i used it on about 1/4 of the problems and still got an 800. when u use a calculator, you might make typing mistakes and stuff. my method is to read the problem and see how to approach it first and then write out necessary work and then use a calculator if necessary. i'm really prone to screwing up my typing in the calculator. as for trig, well, know the basics, you don't need to know every identity. the only thing i plugged in on my calculator were the sequence/series formulas.</p>
<p>well I have a titanium, so it like does everything</p>
<p>I agree with x3rose. I only use the calc on problems that require it, such as finding number of real zeros of a 5th degree polynomial or for certain trig problems.</p>
<p>I use it to solve for things including f(x), etc.</p>
<p>Is knowledge through Algebra 2 enough for this test.</p>
<p>I am gonna be in an advanced class, so should i take this test or the Math IC test?</p>
<p>THanks.</p>
<p>I think Math I...I'm in Precal (well practically done; final on Wednesday), and I think it's vital that you definitely finish Precal for the best score. You could also be really smart though, so I dunno.</p>
<p>how do you do #24 from the practice?</p>
<p>In a group of 10 people, 60 percent have brown eyes. Two people are to be elected at random from the group. What is the probability that neither person selected will have brown eyes? the answer is 0.13..but I don't know why tho..</p>
<p>Hey guys, question 25 is erroneous. The answer is 3.3 for length of AB, but they have it as 3.6. </p>
<p>I solved the problem with 2 different methods, both arriving at the same length.</p>
<p>If I am wrong, please explain why the answer is simply not:</p>
<p>2^2 + 2^2 - 2 x 2 x 2cos(130) ~ 3.3</p>
<p>To above poster, </p>
<p>24 is easily solved using combinatorics:</p>
<p>4C2 = # ways to pick 2 nonbrown
10C2 = total ways to pick any</p>
<p>4C2/10C2 = P(2 nonbrown)</p>
<p>60% have brown eyes, so that means 6 brown, 4 not. For the first person, there are 10 to choose from, and 4 do not have brown eyes, so it's 4/10. And for the second one, you already took one non-brown out, so there are 3 non-brown left out of 9 remaining people. So it's 4/10 * 3/9 = 0.1333</p>