<p>hope I got your attention...
the answer wasn't in the consolidated answer link so here it goes...
In the Blue Book,
pg 674, number 19
If k, n, x, and y are positive numbers satisfying x^(-4/3) = k^(-2) and y^(4/3) = n^2, what is (xy)^-2/3 in terms of n and k?</p>
<p>A. 1/nk
B. n/k
c. k/n
d. nk
e. 1<br>
the answer is:A by the way... please explain them in simple terms... I know some people like intricate way to solve these... but easiest way is fine by me
thanks :)</p>
<p>If x^(-4/3) = k^-2, then x^(-2/3) = k^-1 = 1/k
Similarly, if y^4/3 = n^2, then y^2/3 = n, from which y^(-2/3) = n^-1 = 1/n</p>
<p>So (xy)^-2/3 = (x^(-2/3)) . (y^(-2/3)) = (1/k). (1/n) = 1/nk</p>
<p>damn son. speak english for me</p>
<p>ohhh okay.. I got the stupid variables switched
Thanks a bunch :)</p>
<p>
hopeful, there are more than one post in "Consolidated..." with links to the BB solutions.
You could find /pg 674, number 19/ in the post #9 there.</p>
<p>ooops thanks... I'll be sure to check them next time</p>
<p>Hopeful - I plugged in numbers for k and n and got the answer fairly cleanly using a calculator. See if that works.</p>