<p>December 2010</p>
<ol>
<li>If r>0 and s>0, sq root(r/s) + sq root(s/r) is equivalent to which of the following?</li>
</ol>
<p>F)1
G) 2sqroot(rs)/r+s
H)2sqroot(rs)
J)r+s/rs
K)r+s/sqroot(rs)</p>
<p>Is the best way to solve this problem simply just to plug in two random numbers? Is there an actual effective method besides plugging and chugging for this problem?</p>
<p>You could just break up the fractions like this.
sqrt(r/s) + sqrt(s/r)= sqrt(r)/sqrt(s) + sqrt(s)/sqrt(r)
Combine and you have your answer.</p>
<p>Don’t get how to combine them… ■■■■■</p>
<p>Never mind!! I get it. Oh wow but I would never think of this quick enough on the test.</p>
<p>Haha, now that I think about it my post did look a little vague. Sorry about that. Glad you got it though!</p>
<p>oFg5x3o, your solution is incorrect…</p>
<p>If r>0 and s>0, √(r/s) + √(s/r) is equivalent to which of the following?</p>
<p>F)1
G) 2√(rs)/(r+s)
H)2√(rs)
J)(r+s)/(rs)
K)(r+s)/√(rs)</p>
<p>first you must realize that equation is equivalent to = sqrt(r)/sqrt(s) + sqrt(s)/sqrt(r), in this case the common denominator is √r*√s or √(rs). The top part will be r+s so combine and get that (r+s)/√(rs) is correct answer or K</p>