Math Problem

<p>lol.half the ppl on here did 100,99,98... and the other half did 100,101,102....</p>

<p>Yeah, that was it =D</p>

<p>I wish I could remember what I put for it haha. It was either 45 or 39. So I'm hoping I put 39.</p>

<p>im pretty sure cld_1992 was right because thats how i understood it </p>

<p>im glad i put 39 =)</p>

<p>What method did you all use to get 39?</p>

<p>lol,wow, I read the question wrong, but I still put 39.HAHA</p>

<p>there's probably a much faster way then i did it but i just kept adding 100+101+102+103 etc until i got 3961 meaning the last row was 39</p>

<p>lol
but r u suppose to talk about the questions here???
XPXP
i got 39 btw</p>

<p>i believe i put 139.
why would i have done that??</p>

<p>^I got 139, but the closest answers to that digit-wise were 134 and 39. So I put 39 :)</p>

<p>so what exactly was the value 39 supposed to represent??
39 what??</p>

<p>I think it was how many more seats were in the last row than in the first row in the theater...or something like that.
It said that the first row what 100 and each row after had one more seat than the row in front of it. The beginning said that there was 4,000 seats.</p>

<p>can any one else confirm the question??</p>

<p>The question was if there are 4,000 seats and the first row contained 100 second row contained 101 third row contained 102 etc how many seats will the last row contain</p>

<p>if you keep adding you'll end up with 3961 until you can't add anymore this means the last row was 39</p>

<p>^^^ yeah. That sounds about right.</p>

<p>exactly..so then would the last row contain 139 seats...not 39</p>

<p>im just completely confused about this question was asking</p>

<p>no it asked how much people will be in the last row...</p>

<p>and anyway, if i interpreted the question wrong the answer would have been 134 not 139</p>

<p>can anyone else confirm wat the question was asking??</p>

<p>The question went something like: A the front row of a 4,000 seat theater has 100 seats. Each row has 1 more seat than the one proceeding it, and the remaining seats are placed in the back row. How many seats are in the back row?</p>

<p>Ok, so if each row has 1 more than the one PROCEEDING it, the order definitely went 100, 101, 102,... It only makes sense that row 1 proceeds row 2 and thus row 2 has 101 seats. To solve the problem all you had to do was add 100+101+102+... until you reached 3961, then you subtract to figure out that 39 seats were in the last row.</p>