<p>xy = x + y</p>
<p>If y > 2, what are all the possible values of x that satisfy the equation above?</p>
<p>(A) x < 0
(B) 0 < x < 1
(C) 0 < x < 2
(D) 1 < x < 2
(E) x > 2</p>
<p>the answer is D.</p>
<p>can someone help me with this problem? thanks.</p>
<p>x = xy - y
x = y(x+1)
y = x/ (x+1)</p>
<p>Put that in a graphing calculator</p>
<p>D is the only one that words</p>
<p>Correction:</p>
<p>x = xy - y
x = y(x-1)
y = x/ (x-1)</p>
<p>since y >2, so: x/(x-1)>2 which means:
(1) if x-1>0, then x>2(x-1)=2x-2 => x<2,
(2) if x-1<0, then x<2(x-1) => x>2, which is an impossible situation. (how can x-1 <0 yet x>2). So this is not a soultion.
Therefore, (1) is the only solution, which gives x-1>0 and x <2, which is equivalent to:
1>x>2.</p>
<p>thanks for the help</p>