<p>Can anyone please help me with these 2 problems?</p>
<ol>
<li>Meredith has a red hat, a blue hat and a white hat. She also has 3 sweaters- one red, one blue and one white- and 3 pairs of jeans- one red, one blue and one white. Meredith wants to wear a red, white and blue outfit consisting of one hat, one sweater and one pair of jeans. How many different possibilities does she have?</li>
</ol>
<p>(A) 3
(B) 6
(C) 9
(D) 12
(E) 27</p>
<ol>
<li>If n is a positive integer and 2^n + 2^(n+1)= k, what is 2^(n+2) in terms of k?</li>
</ol>
<p>(A) (k-1)/2
(B) 4k/3
(C)2k
(D)2k+1
(E)k^2</p>
<p>For #2:</p>
<p>Split up 2^(n+1), and you get 2<em>2^n.<br>
Now you have 2^n + 2</em>2^n = k.
That’s the same as 3*2^n = k.
so, 2^n = k/3</p>
<p>Split up 2^(n+2).
You get 4<em>2^n.
You already know 2^n = k/3.
So, the answer is 4</em> (k/3)
Final answer = 4k/3 (B)!</p>
<p>I’m not 100% on this but I think you find out how many colour options you have for the sweater which is 3. For the jeans you then have 2 colour options because you’ve already used one previously. For the other thing you have 1 left because you’ve again used the other 2 colours.</p>
<p>Times all those together: 3 x 2 x 1 = 6 </p>
<p>Am I right?</p>
<p>Edit: I was right after all.</p>
<p>thanks for the help 
really appreciate the kindness.</p>