<p>Assuming the very first one, the image is a little small but this is what I read it as:</p>
<p>If x < y < 0, which of the following must be true?</p>
<p>I: x+1 < y+2
II: 3x < 2y
III: x/y > 1 (I’ll skip typing the answer choices)</p>
<p>I: x is less than y, so x+1 < y+1 < y+2, so I is true.</p>
<p>II: This is also true. 3x < 2x < 2y.</p>
<p>III: This is true. If you multiply both sides by y (and reverse the inequality sign), you obtain x < y. Hence, III is true if and only if x < y, so it must be true.</p>
<p>Hence the answer is E, I,II,III.</p>
<p>You should have subtracted b ( or 30 ) before you divided by 2. </p>
<p>Sum = 100
Median (b) = 30</p>
<p>2( a + b) + 30 = 100
2( a + b) = 70
( a + b) = 35</p>
<p>Also, #15 (the one with the tournament) can easily be solved by noting that there are 6C2 = 15 ways to choose two players for any game. Each player plays twice, so the answer is 2(6C2) = 2*15 = 30.</p>