Math Question help plz

<p>1.The Venn diagram above refers to 250 students and their extracurricular activities. Each student participates in at least one of the three kinds of activities shown. Of all the students who participate in sports, how many of them also participate in drama?
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<p>2.The 20 numbers in list A have an average (arithmetic mean) of 9.5. the 10 numbers in list B have an average of 8.3. If the two lists are combined to make a new list, what is the average of the 30 numbers in the new list?</p>

<ol>
<li><p>First we want to find x. 250= 58+21+35+ x+ 26+50+40 , x=20. We want the number of students that play sports and do drama, so that is the intersection of regions 21 and 20, so the answer is 20+21=41</p></li>
<li><p>Let A be the sum of the 20 numbers in list A and B be the sum of the numbers in list B.</p></li>
</ol>

<p>Average= sum/# of terms, so for list A, 9.5=A/20 -> A= 20(9.5)= 190. For list B, 8.3=B/10 -> B=83.</p>

<p>When you combine the two lists, there are 30 terms, so the sum is A+B and the average is therefore (83+190)/30 = 273/30 = 9.1</p>

<p>Thank you very much, ur explanation was really good</p>

<p>For #15 in that document, the answer is 6760, correct? (26)(26)(10)?</p>

<p>A company labelts its product witha three- character…
The answer is (26)(26)(10)=6760</p>