<p>You don’t need to know he lengths of the sides. All you need are the ratios, which you can find by using the characteristics of special triangles (30-60-90) and (45-45-90).</p>
<p>I’m guessing that AB = BC = CD = DA = BD, but I don’t want to assume stuff. If that’s the case, then just use 30-60-90 triangles.</p>
<p>You can determine the ratios of the side lengths given the angles, because all triangles with three given angles are similar to each other. In general, the ratios are determined using the law of sines.</p>
<p>^ I agree! The law of sines is an under-appreciated rule. Because of where it falls in the curriculum (and how it is presented), many students don’t realize that it applies to right triangles! And that if you have any trouble with 30-60-90 or 45-45-90 triangles, the law of sines can make all that trouble go away.</p>
<p>(Still, the students who are comfortable with law of sines tend to be the ones who have no trouble with the special right triangles anyway…)</p>
<p>They never teach the law of sines applied to 30-60-90 or 45-45-90 triangles because it’s usually easier to just memorize the ratios. But what they forget to teach is that these ratios obviously come from the law of sines. Similarly, the Pythagorean theorem is just a special case of the law of cosines.</p>