<p>Please try to answer the question below, and explain how you got to your answer, any help appreciated :)</p>
<p>1,2,3
if m, n, and k are to be assigned different values from the list above,
how many different values will be possible for the expression (m + n)^k ?</p>
<p>(A) Three
(B) Four
(C) Five
(D) Eight
(E) Nine</p>
<p>Just substitute the given values for all of them, solve, and count. Quickly.</p>
<p>(1+2)^3 = 27
(1+3)^2 = 16
(2+1)^3 = 27
(2+3)^2 = 25
(3+1)^2 = 16
(3+2)^1 = 5
(2+3)^1 = 5</p>
<p>27, 25, 16, 5</p>
<p>Four values.</p>
<p>^ The answer is (A) Three, and is there no systematic way to solve this question? Perhaps using combinations</p>
<p>3 values.
27, 16, and 5</p>
<p>1, 2, and 3 can be the xponent: therefore there are 3 different values. the 2 numbers in brackets can be in any order and will both be equivalent.</p>
<p>I’d just list and count. I believe that qwerfsad is correct, but there’s no way I’d have known that if this were on the SAT. Since you only have 3 numbers and 6 different ways of arranging, it won’t take too much time to list and calculate.</p>
<p>ok, I guess the best way to solve it is to plug in then.</p>
<p>the numbs inside will always be the same</p>
<p>so the exponents matter</p>
<p>3 diff exponents so [3]…</p>