<p>BB
Practice test #5
section 7
Q no. 20.</p>
<p>Thanks in advance!!</p>
<p>Bump!!!</p>
<p>If you post the question, you will be more likely to receive help.</p>
<p>^ Lol seriously. BB? What’s that? Baron’s book? If you need help, quit being lazy and at least post the question so people can try to help.</p>
<p>I dug up my book. The function is simply translated down two (k=-2) and right 3 (h=-3). </p>
<p>(-2)(-3) = 6, which is choice (E).</p>
<p>@yosup
BB…DUH??? THE BLUE BOOK>>>>>>>>>>>>>>>>>>>>>>>RING ANY BELLS?? THE OFFICIAL SAT STUDY GUIDE???
@silver
The reason i didn’t type the question is that it had a graph.
Silver turtle thanks…whoa that wasn’t hard.
i was putting trying to solve the two simultaneous equations in terms of h and k and was lost while trying to solve them.
Thanks again.</p>
<p>@Duke can you plz explain this.</p>
<p>BB, Pg 400…q-18 why is the answer D…coz II can be correct too…isnt it?</p>
<p>and pg 427 q-17 why is the answer E?</p>
<p>@gurung
Pg 400
the question says MUST be. not COULd be. So II is not true for all cases. For instance when b=2, a can be less than 2.
Pg 427, 17?? i think u mean q-15.
the length of PQ is 6. which means that the x- coordinate of Q is 3 and x coordinate of P is -3 (by symmetry)
Putting x=3 in y=x^2 we get the y coordinate of Q.
Then putting both the coordinates of Q in y=a-x^2 we can solve for a.</p>