<p>Ok on the Sat on 4/1 i had a math question that said "there are 5 consecutive integers whos sum is 5n+10, what is the median of these integers in terms of n?", now the answer i believe i n+2, but there was no choice like this, am i just doing this wrong or should the answer really be n+2, btw i sat there for almost 5 mins and im pretty sure n+2 was not a choice</p>
<p>ya, you would think that if it asked for the median you would divide the number by the number of integers, which is 5, giving you n+2. maybe i'm missing something as well</p>
<p>Wasn't the question "3 consecutive odd integers, where n is one of the odd integers?" or am I thinking of something else?</p>
<p>im 99% sure it was 5 consecutives</p>
<p>i remeber getting 2n+1 because you had to double the n and half the 1 from n+2, as was the general trend for the series</p>
<p>what general trend from the series? does it not go n,n+1,n+2,n+3,n+4</p>
<p>Haha :D</p>
<p>Obviously n must be in each of the 5 integers. Now, what five consecutive integers have a sum of 5? -1, 0, 1, 2, 3</p>
<p>So the median is n+1.</p>
<p>^their sum is 5n+10, not 5</p>
<p>It said 10n + 5</p>
<p>so...</p>
<p>(2n-1)+(2n)+(2n+1)+(2n+2)+(2n+3)=10n+5</p>
<p>middle term was (2n+1)</p>
<p>ahh damn, thanks for clearing it up though</p>