<p>Dmn shame...one wrong answer...</p>
<p>When the three Adams children went to school one morning, they each took one of the other's lunches. In how many ways could the three children have been paired with the lunches so that no one took his or her own?</p>
<p>Not really sure, but here’s the thread explaining it: <a href=“http://talk.collegeconfidential.com/sat-preparation/246314-how-do-you-do.html[/url]”>http://talk.collegeconfidential.com/sat-preparation/246314-how-do-you-do.html</a></p>
<p>ooh tough. I think the answer’s two. Think about the three kids as A, B, and C. Let’s say A chose first. He can choose between B and C’s lunch, so that’s TWO choices. Then it’s B’s turn. B can take A or C’s lunch, which is two choices, but we have to subtract A’s choice from this. B has ONE choice. Then C has no choice. he can only take which ever lunch is left over. </p>
<p>2 x 1 = 2 combos :)</p>
<p>oh…gee thank you!</p>