<p>someone explain #49 in math for me. how do i do it algebraically? the answer is C.</p>
<p>We have 8 = 2^3 and 4 = 2^2. So 8^(2x+1) = (2^3)^(2x+1) = 2^(6x+3) (using the property that (a^b)^c = a^(bc)).</p>
<p>Similarly, 4^(1-x) = (2^2)^(1-x) = 2^(2-x).</p>
<p>Equating the exponents, we have 6x+3 = 2-2x, so x = -1/8.</p>
<p>thanks bro!</p>