<p>{1/cos@ - sin@/tan@) (cos@) =</p>
<p>a. cos@
b.sin@
c. tan@
d. sin(squared)@
e. tan(squared)@</p>
<p>i dont know how to write the exponent, so i put squared...:P</p>
<p>i saw this excercise and i really dont know how to do it. If anyone can help, please</p>
<p>The answer is D, sin^2@.</p>
<p>here's why</p>
<p>{1/cos@ - sin@/tan@) (cos@)</p>
<p>distribute the cos@ you get
cos@/cos@ - sin@cos@/tan@</p>
<p>the first expression is 1</p>
<p>sin@cos@/tan@ = sin@cos@ * cos@/sin@
because dividing by a number is like multiply by its reciprocal, and tan@ = sin@/@cos</p>
<p>so therefore the sin@ in the numerator and denominator cancel out, and you're left with cos^2@</p>
<p>which means the whole equation is now
1 - cos^2@
and we know this equals sin^2@
from the identity
sin^2@+cos^2@ = 1</p>
<p>Hope that helps.</p>
<p>the answer should be d.
(1/cos@ - sin@/tan@) (cos@)=(1/cos@ - sin@ / (son@/cos@)) ( cos@) = (1/cos@ - cos@) (cos@) =1-cos(square)@
because sin (square)@ + cos (square) @ = 1
1 - cos(square)@ = sin (square) @</p>
<p>multiply to get 1 - cos<em>sin/tan
= 1- (x/r)(y/r)/(y/x)
=1 - x</em>x/r*r
=1 - cos(squared)
=sin(squared)</p>
<p>thanks (10 char)</p>