<p>I need to convert this to polar form but have no clue how</p>
<p>y^2-8x-16=0</p>
<p>bump also is this right (notes from the section)</p>
<p>x^2+y^2=(3cos(theta))(3cos(theta))
= 3x</p>
<p>I need to convert this to polar form but have no clue how</p>
<p>y^2-8x-16=0</p>
<p>bump also is this right (notes from the section)</p>
<p>x^2+y^2=(3cos(theta))(3cos(theta))
= 3x</p>