<p>1) tx + 12y = -3 </p>
<p>the equation above is the equation of a line in the xy -plane, and t is a constant.If the slope of the line is -10,what is the value of t?</p>
<p>1) tx + 12y = -3 </p>
<p>the equation above is the equation of a line in the xy -plane, and t is a constant.If the slope of the line is -10,what is the value of t?</p>
<p>Rearrange into y = mx+b. </p>
<p>You have:</p>
<p>12y = -3-tx
y = (-3/12)-tx/12
so -t/12 is the slope, i.e., -10 = -t/12, i.e., t = 120.</p>