<p>if the length of each edge in a cube is increased by the same percent and teh result was that a cube had 25% more volume than it originally had, by what percentage were the edges increased?</p>
<p>OK lets see.
cube volume= L^3 good?
v=L^3
1.25V= X^3
do the algebra, solve for L and X , then (X-L)/L
this is too complicated,lets try plugging in # lol.
OO, i realize some good numbers...
originally, L=10, V=1000
now~ V= (1000) (1.25) = 1250
cube root that~ L approximately ~ 10.77
(10.77-10 )/10=77%?</p>
<p>35.35^3 is like 44000, that can't be right.</p>
<p>The cube root of 1250 is 10.7721.</p>
<p>So, (10.7721 - 100/10 = .077
.077 * 100 = 7.7 % larger.</p>
<p>lol my bad, 7.7% yeah</p>
<p>Lets set up equation.
Y is the percent times X, the sides.
We're told that increasing X by Y will result in the product being 25% more than the original (X^3)</p>
<p>(xy)^3 = 1.25(X^3) Remmber the parenthesis </p>
<p>X^3Y^3 = 1.25 (X^3)
y^3 = 1.25
1.25^1/3 = 1.077 = 7.7% </p>
<p>Ite son im outtttttttt</p>