<p>The interior dimensions of a rectangular fish tank are 4 feet long, 3 feet wide, and 2 feet high. The water level in the tank is 1 foot high. All of the water in this tank is poured into an empty second tank. If the interior dimensions of the second tank are 3 feet king, 2 feet wide, and 4 feet high, what is the height of the water in the second tank?</p>
<p>Answer is 2 feet. I got it wrong then sorta understood it, but lost it again. is the hight of the fish tank even relevant? Thanks!</p>
<p>The height of the fish tanks are not relevant; only the widths and lengths are. Why? Because no matter how high/tall the fish tanks are, the water level won’t change.</p>
<p>If you have a glass that is 10 inches tall, and it is filled with water 4 inches high, then if you transfer the water to another glass with the same circumference and diameter but a height of 20 inches (to go to an extreme…), the height of the water level will still be 4 inches. ;)</p>
<p>ahh thanks but I also need an explanation on how to do it.</p>
<p>Simple: The first tank’s area of the base (when you disregard the height) is 4x3=12, with a water level of 1 foot. The second tank’s area is 3x2=6. It’s half as small, so the water will be twice as high. 1x2=2 feet. :)</p>
<p>I hope you don’t mind if I decided to join in too. I’m reading from the blue book, not sure which version (how do you check?)</p>
<p>Question: Does the equation 3x + 6y = 47 have a solution in which x and y are both positive integers? </p>
<p>Their explanation didn’t make sense to me, can someone explain it further?</p>
<p>Explanation: Note that 3x = 6y = 3(x + 2y). Therefore, for any positive integers x and y, the sum 3x + 6y = 3(x+2y) is a multiple of 3. But 47 is not a multiple of 3. Therefore, no matter what positive integers you choose for x and y, the sum will not be 47. Thus, the equation 3x = 6y = 47 does not have a solution in which x and y are both positive integers.</p>
<p>What kind of SAT question is that?</p>
<p>There are no yes or no questions in the SAT.</p>