<p>couldnt find an easy way to do this so what i did was a^3 * b^2 = 432, and just plugged in a random number for a, solved for b, and looked through the 5 solutions... is there another way to solve this?</p>
<p>what i would do is break 432 down to its prime factors
so you’d get 2^4 * 3^3
and then, what you did, you’d have a^3<em>b^2 = 3^3</em>2^4
and rewrite 2^4 as 4^2
so you’ll see that a = 3 and b = 4
so the product is 12.</p>
<p>I will solve this math roblem with more wild method=)</p>
<p>a^6/2<em>b^6/3=432
a^3</em>b^2=432
and then think what digits could replace a and b => 27<em>16 => 3</em>3<em>3</em>4<em>4=>3^3</em>4^2
=>a=3 and b=4 => 4*3=12.
Answer: 12.</p>
<p>a^(3) * b^(2) means that a * a * a * b * b = 432.
Factor 432 = 2 x 2 x 2 x 2 x 3 x 3 x 3
You have four 2s and three 3s.
a = cube root of 27 = 3
b = square root of 16 = 4</p>