<p>If n is a positive integer and 2^n + 2^(n+1) = k, what is 2^(n+2) in terms of K?</p>
<p>Answer: 4k/3</p>
<h1>17, 18</h1>
<p>on BB 2nd pg 468!!!</p>
<p>I used plug ins, which for me was quicker, but you can factor out the 2n and solve for ‘k’</p>
<p>2^(n+2)=2(k-2^n)=2k-2^(n+1)
2^(n+1)=k-2^n
2^(n+2)=2k-(k-2^n)=k+2^n
2^n+2^n*2=k
2^n=1/3k
2^(n+2)=k+1/3k=4/3k</p>