<p>These 2 math questions on a Kaplan’s test really bothered me. Can anyone explain the answer to me because I really think they are wrong…?</p>
<li><p>At a basketball game involving 8 teams, each team played 4 games with each of the other teams. How many games were played at this tournament?
THEIR solution: 1. 8x4 = 32 games played. 2. 32(8/2) = 128, 8/2 since each game involved 2 teams. ANSWER: 128
MY solution: 112… if there are 8 teams and they all play each other then they would play 7! games which means = 28 games. Then multiply it by 4 so ANSWER: 112.</p></li>
<li><p>The length of 2 sides of a triangle are (x-2) and (x+2), where x > 2. Which of the following ranges includes all and only the possible values of the third side y?
THEIR solution: (x-2) + (x+2) > y, 2x>y… then because y represents the value of the side of a triangle, it must be greater than 0. ANSWER: 0 < y < 2x.
However, this answer seems quite wrong since if y is bigger than 0, then it can be like 1 or something.
MY solution: greater than difference of the 2 sides: (x+2) - (x-2) < y = 4 < y & smaller than sum of the other 2 sides: (x+2) + (x-2) > y = 2x > y
so… 4 < y < 2x</p></li>
</ol>
<p>Thanks to anyone who replies!</p>