<p>so ya just some math questions from BB 2nd Edition Practice Test #2
Section 2 pg. 457
20. In the xy-coordinate plane, lines l and q are perpendicular. If line l contains the points (0,0) and (2,1), and line q contains the points (2,1) and (0,t), what is the value of t? </p>
<p>Section 5 pg. 467
14. f(x) = |3x-17|
For the function above, what is one possible value of a for which f(a) < a?</p>
<p>Section 8
13. If n is a positive integer and 2^n + 2^n+1 = k, what is 2^n+2 in terms of k?</p>
<ol>
<li><p>You can find the slope of line l, and then the slope of line q is the negative reciprocal because it’s perpendicular. Now you have a slope and a point given (2,1) for q, so you can find the equation and then plug in 0 to get the value of t.</p></li>
<li><p>I’d just graph this and the line y=x. if a point is below the line y=x, that means the y value [or f(a)] is less than the value of x. So find a point on the given function that’s below the line y=x.</p></li>
<li><p>You can use rules of exponents to break this down. 2^(n+1) equals 2^n times 2^1, or (2^n)(2). Thus k=2^n + 2(2^n) = 3(2^n)
2^(n+2) is, similarly, 2^n times 2^2, or 4(2^n). that’s (4/3)k.</p></li>
</ol>
<p>just bumping this instead of making a new topic </p>
<p>It’s a triangle and points are A, B, and C</p>
<p>In the figure, AC = 6 and BC = 3, Point P (not shown) lies on segment AB between AB such that segment CP is perpendicular to segment AB. What is the length of segment CP?</p>
<p>no there isnt but i know there are two 90 degree angles cuz of perpendicular lines, im pretty sure thats all the problem i would draw the figure but im not sure how to do that or mayb like this<br>
B
/ \ Note: Figure not drawn to scale
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/
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A C</p>