Math Questions

Test Preparation SAT Preparation
1

<p>1In the coordinate plane, the points F(-2,1), G(1,4), and H(4,1) lie on a circle with center P. What are the coordinates of P?</p>

<p>A(0,0)
B(1,1)
C(1,2)
D(1,-2)
E(2.5,2.5)</p>

<p>2 if 0 is less than eq to x which is lessthan eq to y and (x+y)^2-(x-y)^2 is greater than or equal to 25, what is the least possible value of Y?</p>

<ol>
<li>In rectangle ABDF above C and E are midpoints of sides BD and DF respectively. What fracion of the area of the rectangle is covered.</li>
</ol>

<p>I don't have a way to show this but its basically</p>

<p>B----c----D
| /\ |
| / sdf |
| / s ds ds
A---------F</p>

<p>Where there is a line formed from CA and CE. and the area inside that is shaded.</p>

2

<ol>
<li><p>try drawing it w/ accurate scales to see if you can visually see it, if not, then use formulas </p></li>
<li><p>expand the 2 squared ones, you should get
4xy >= 25</p></li>
</ol>

<p>now think, least possible value of y is also the max value of x.
so, x= y
y*y = 25/4
y = 5/2 </p>

<ol>
<li>not sure if im seeing this correctly, so trianglges ABC and CDE are shaded?</li>
</ol>

<p>alright, let AB = 1. BD be = 1 as well to simplify matter.
C is midway, so BC = 1/2
area of triangle ABC = 1/2 bh = 1/2 * 1 *1/2 = 1/4</p>

<p>area of triagnle CDE = 1/2 * (1/2)(1/2) = 1/8, or just observe from the shaded triangle in the square(rectangle).</p>

<p>now, ABC+ CDE = 1/8+1/4 = 3/8</p>

<p>portion of area/ whole area = 3/8 / 1 = 3/8</p>

3

<p>1,find the only point which has equal distance between all these 3 points.
2,…is the answer 5/2?..let x=y 4xy=25 xy=25/4 y=5/2
3,S=AB</p>

4

<p><a href=“http://www.gdn.edu/Faculty/mzabdawi/SAT/S2.pdf[/url]”>http://www.gdn.edu/Faculty/mzabdawi/SAT/S2.pdf&lt;/a&gt;&lt;/p&gt;

5

<p>For future references, it might be easier to provide the origin of the test. In this case, it was a test known (among other years) as the Official Practice Test 2007-2008.</p>