<p>Let f(x)=3 + x^2 + tan(πx/2), where -1<x<1</p>
<p>Find f^-1 (3)</p>
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<p>That is a pi sign in the parentheses and the question asks for f-inverse of 3</p>
<p>f^-1 (3) = 0</p>
<p>How did you find the inverse of that equation, though? I don't understand how to do it with tan in the equation.</p>
<p>f(0) = 3.
Point (0,3) is on the graph of y=f(x).
It translates into point (3,0) on y=f^-1 (x), so
f^-1 (3) = 0</p>