MAY 2005 TEST – FORM TWO(math experimental)

<p>Yea I don't see how its 36...</p>

<p>sorry dude...</p>

<p>the answer is 20 has to be</p>

<p>wait let me think this through</p>

<p>wait wasnt the 36 problem and the 20 problem 2 different problems?</p>

<p>uh oh unless the combinations cant be the same as another</p>

<p>he got 36 as the answer to the 20 question.</p>

<p>then it wont be 20</p>

<p>my body is still in pain from those 4 hours sitting this morning</p>

<p>that would make it less than 20 anyways, not more than 20</p>

<p>ooh ok, so what exactly was the 20 question
(dont yell at me)</p>

<p>NO IT's 36 -- the one u all think is 20 is actually 36 !!!!!!!!!!</p>

<p>kingsfan i think theyre 2 different problems?
*can someone clarify this PLEASE?</p>

<p>x's even number 4 less than equal to x less than equal to 10, y integers 4 less than y less than 10, how many possible (x,y) combinations=20; (4,6,8,10 for x) and (5,6,7,8,9 for y) 4*5=20</p>

<p>damn it, i think they fooled us, its probably isnt 20 since you will get combinations with the same numbers therefore they are not different combinations</p>

<p>i want my scoreeeee lol two weeks from monday</p>

<p>for this reason:<br>
5 possible corrdinates where 4 is first
4 possible cordinates where 5 is first
7 possible cordinates where 6 is first
4 possible coordinates where 7 is first
7 possible cordinates where 8 is first
4 possible coordinates where 9 is f irst
5 possible coordinates where 10 is first</p>

<p>add up all those numbers [the first ones i listed ] and it = 36</p>

<p>diamond t, it has to be 20 try to name one that is a double</p>

<p>mnjets' explanation is correct--</p>

<p>the answer to the (x,y) combo problem is</p>

<p>20</p>

<p>is that not right?...problem = a bit tricky</p>