<p>Whoa whoa wait a minute… that’s like 35.5 RAW that your friend got for an 800??? Is there still hope for a 40 raw? Lolll or all of his guesses were correct and he got the 43-800 T_T</p>
<p>i panicked horribly (my first sat 2 test ) …
i think i got half of them wrong =[
i took the CB practice test at home and got a 800
i can’t believe this happened. i dunno what happened to me.
i am in my Great Depression =[</p>
<p>can someone explain the cubic question?</p>
<p>I put
(x^6)(y^15)(z^21)
which was answer D, I think</p>
<p>The original equation was
(x^2)(y^5)(z^7)
and I just raised the whole thing up to a cube. That was the safest choice and 100% guaranteed that you can take the cube of that function.</p>
<p>Same here dude it was my first sat II as well… I think I also panicked and ran out of time before I got to like 5 of them… also made some stupid mistakes here and there…</p>
<p>f(x) = x^4-4x+1
f(x+2) = ?
Answer was that the two graphs cross only at one point.</p>
<p>It was that they cross at one point and the have the same range so that was II and III… i graphed it</p>
<p>Sensei, I confirm.</p>
<p>You graph
x^4-4x+1
and
(x+2)^4-4x+1</p>
<p>They intersect and 1 point, but don’t have the same zeros, because they have the same slope and are shifted.
I forgot the 3rd choice</p>
<p>can someone explain the cubic question?</p>
<p>Well he might’ve guessed right! It was definitely 43 or less, but most likely within the 42-43 range. No way 35.5 can be an 800 xD.</p>
<p>didn’t graphs have same range as well as 1 intersection?</p>
<p>^ yea i put II and III</p>
<p>@zhaoqirock - The third choice was “they have the same range”</p>
<p>Here is the trigonometric function that asks to find the period:
f(x) = 3sin(pi<em>x) + cos(2pi</em>x)
I don’t think graphing is the best way to attack this problem.</p>
<p>You graph
f(x)= x^4-4x+1
f(x+2) = (x+2)^4- 4(x+2) + 1</p>
<p>@Sensei
Then how do you do it?
I graphed it and I got the answer no problem.</p>
<p>If you graph it and zoom in, you can look at the graph where it looks like it’s repeating, so the period comes out to be 2. I doubted myself because each period does not look absolutely the same.</p>
<p>zhaoqirock, how sure are you of that answer? If you can really prove that that’s the answer, I probably won’t consider cancelling my score (since I got D as well).
EDIT: talking about the cubing thing</p>
<p>what exactly did the cube question ask?
i guessed B</p>
<p>^ Plane M is 6 units from point C. What is the area of points in plane M such that the points are not more than 12 units from point C.</p>
<p>Use the pythagorean theorem to get that the other side, which is the radius, is sqrt(108). To find the area of the circle, which is the set of points, do (pi)r^2=108pi=339.</p>
<p>@ Krazy</p>
<p>Well, since the answer choice for E was:
(x^8)(y^75)(z^some really big number, presumable 7^3)
I figured that the question was testing if we know how to distribute exponents and if we know that when you have a power to a power, you multiply the answers, not power it.</p>
<p>Therefore, in my mind, choice D seemed plausible.
(x^6)(y^15)(z^21)</p>
<p>You can take the cube root of those values and get a whole number no matter what, as long as x,y, and z are integers. </p>
<p>I didn’t know how one could even get the answers from A, B, or C, either.
If anyone knows how to do the problem for sure, please tell me? But for now, I’m 90% sure that the answer is D, unless you can somehow simplify that answer and still get whole numbers when you cube root it.</p>
<p>Cubic question: this is kind of the cheat way out of it, but I chose three prime numbers (3,5,7) and plugged them into the equation and divided by the other equation to see which one it was divisible by. The answer turned out to be B.</p>