<p>obutto, no because they don’t all add up to the first digit.</p>
<p>was 8 letter C for the triangle one? cuz thats what i put</p>
<p>ahh dam, now i just realized all three were true dam
thats 2 wrong so far</p>
<p>Was it not 9540?</p>
<p>0 was not a viable choice based on III</p>
<p>^0 couldn’t be a number</p>
<p>robo.mind it was all three conditions. Answer was E. Also the question before that with the median was 26. The last question in the section was B^2 + B</p>
<p>I also got I, II, and III to be true.</p>
<p>Probably not b/c everyone is posting answers now.
btw…is there a posting for MAY SAT CRITICAL READING yet??</p>
<p>@robo.mind </p>
<p>What if one of the numbers was 0? Then II cannot work.</p>
<p>Did anyone have this question? (or was it experimental?)
2(a+b)+c=38
2(a+c)+b=40
2(b+c)+a=42
If each letter (a,b,c) stands for a side of the triangle, what is the perimeter?
A) 24
B) 36
C) 40
D) 60
E) 120</p>
<p>Yes median was 26 and the last one was E B^2 + b</p>
<p>Does anyone remember the question with the quadrilateral and a triangle was cut out of it and you had to find the area? Was it >91 or <91?</p>
<p>I normally do the best on math but this test really slayed me…I skipped like 3 and am unsure on 1-3 of them… Surprisingly the other 2 sections were easy… Sigh</p>
<p>obutto, it said in the question that x does not equal y
then 0 can not be one of the digits. They must be different</p>
<p>Here were my answers:</p>
<p>2/3
60
E
6
8, 16
4 Pi
7/8
42
7.8
6
72
102
36
4
5
3/4
1000
8521</p>
<p>12
15
16
1:04-1:08
2c-5 = b and bc= 45
24 - 4 pi
20p
3
7
36
100
232 223</p>
<p>91
32
Square root of 6, square root of 13
5
6a +15p
26
3
b squared +b</p>
<p>2
2/5
8
750- 150w
50
5
20 pi
2
77
RS00J0
1/4
8
2x + x squared
-7x+13
1/4 r squared less than r +5 less than r-5 squared</p>
<p>moneymaster, that question was experimental.</p>
<p>itsinreach, it can’t be 9540 because it multiplies to 0 and the question said that it was a factor of 10, but not 0.</p>
<p>Thanks sAxsKy…good thing it was…lol</p>
<p>Anything times 0 is zero. I think we’re talking about the wrong question. I’m talking about the one where everybody says its I , II, and III</p>
<p>area of quadrelateral was 105???</p>