MIT gets record 11,213 apps for the Class of 2010

<p>20% of the applications were from internationals</p>

<p>There were 377 EA admits from 3,098 EA applications.</p>

<p>The total number of apps received for the Class of 2010 (including the EA apps) was a record 11,213, of which a bit over 2,500 were international applicants.</p>

<p>It is anticipated that around 1,500 total will be admitted, for an estimated overall admit rate of around 13.5%.</p>

<p>(Last year, there were 384 admitted EA, from a total of 2,794 applicants,plus another 267 from the 2,240 EA deferreds) and an overall 1,494 admits.)</p>

<hr>

<p>An interesting tidbit from an interview with the Director of Admissions, Marilee Jones (The Tech, Jan 18, pp 1, 18):</p>

<p>"Currently Harvard and Yale are the only two schools to which MIT loses more students than it wins, with Harvard winning over two thirds of the joint admits. MIT loses few students to other schools of technology, Jones said."</p>

<p>wow, that's a lot of people.<br>
just wondering if byerly or anyone could inform me, how does cross-admitting work? i mean, will harvard and mit talk to each other to see if the same person applied to both schools and then partly base their decision on that?</p>

<p>make that 11,212. I withdrew mine yesterday.</p>

<p>No, Squiggle88, they don't talk to each other. Cross-admitting just means that a given student was admitted to more than one of the schools in question; no discussion amongst admissions departments need be involved.</p>

<p>Given the rising yield (percentage of admitted students who matriculate) and the over-subscribed classes the last two or three years, if I had to guess I'd guess that they will admit slightly fewer this year than last year.</p>

<p>In the EA round, they admitted 377 down from last years 384.</p>

<p>This 1.82% decrease implies that they will admit 1466 this year.</p>

<p>This means they have 1089 spots left to fill with the remaining applicants.</p>

<p>11212 - (377 EA + 216 rejected)=10619</p>

<p>1089/10619=10.3% chance of acceptance in RD round.</p>

<p>This accompanies a 1466/11212=13% overall acceptance rate.</p>

<p>Not all EA admits will matriculate.</p>

<p>What's your point?</p>

<p>A factor your formula doesn't take into account</p>

<p>Spartan's formula was for acceptance percentages, not matriculation.</p>

<p>What is going to happen to the number of other international students admitted.</p>

<p>right...so they will accept more than simply the 1089 spots they have to fill.</p>

<p>Spartan is speculating that they will admit ~1466 this year, and having already admitted 377 EA applicants, that leaves 1089 further acceptances. They do not have 1089 spots to fill: each class size is targeted to be ~1000 (not ~1100), based on housing, course availability, resources, etc. For the past several years, a larger percentage of admitted students matriculated than expected, leaving the class sizes larger than can be accommodated appropriately. That can't continue indefinitely. If last year's increased "yield" of 67% and the jump in applications this year is a predictor, you may want to assume that yield also rises, perhaps to 70%. (Perhaps this is a bad assumption, we won't know until May.) If 70% of Spartan's postulated 1466 acceptances decide to attend, class size would stand at 1026, which is about right. I believe that is what Spartan was trying to say, anyway. (Seanthebomb07, there have not yet been <em>any</em> international students admitted to the Class of 2010. These students are only admitted as part of the RD round, which is in reading now.)</p>

<p>I have no way to know what numbers Admissions is working towards this year, but Spartan's guesses do not seem to be out of the ballpark. We'll know some of the numbers in late March, and the others in May.</p>

<p>Good luck everyone!</p>

<p>One thing you haven't taken into account is the quota for international students. </p>

<p>Given the 8% quota and a total of only about 1500 admits, we can estimate a max of 120 accepts for international students. So internationals will have a rate of about (120 international accepts) / (1500 class size) = 8%</p>

<p>Then, since 92% of the remaining class will come from domestic, we can say (1500 admits - 120 international admits) / (11213 applicants - 2500 international applicants) giving a domestic acceptance rate of about 15.8%</p>

<p>The increase in applications was primarily from internationals, which are limited to 8%. I'm not sure of the difference in the number of domestic applicants between 05 and 05, but it seems like it might have decreased or remained about the same. Anyone with more statistics?</p>

<p>Also, here are some of the statistics I had calculated based on last year's data. Might not help much, considering the spike in international applicants, but could be valuable to someone. </p>

<p>Overall Chances EA = 23.30% (including deferred students who were ultimately accepted)
Overall Chances RD = 13.46% (excluding deferred students, only "new" RD applicants)</p>

<p>Within the RD pool itself, EA deffered students have about an 11.92% chance at acceptance, which is only a little behind the typical non-EA, RD pool applicant.</p>

<p>can someone please tell me what'll happen to the transfer rate? thanks.</p>

<p>im not sure this has much to do with the transfer rate. iirc, the transfer rate goes up or down depending on how many students leave MIT (which isnt much)</p>

<p>Transfer rates won't really be affected. Since they only admit a few per year, because only a few leave, I doubt the rate will fluctuate much. As JSuresh correctly put it, the rate is largely determined by the number of students which leave MIT.</p>

<p>mootmom- thanks!!! :)</p>

<p>On the cross-admit thing: the tech really messed up the article. I don't think some parts of it are true (Y specifically?). See Ben Jones's MIT blog.</p>

<p>(I stink at grammar)</p>

<p>Read further in the Blog, and you will see that the cross-admit edge for Yale last year was accurate, no matter how narrow it may have been.</p>

<p>im an EA admit, and im not matriculating... </p>

<p>:)</p>