<p>It’s me, the math dunce again. Here’s two more math problems from an old SAT exam I’d like some help on. </p>
<li>Circle C has radius of sqrt 2. Squares with sides of length 1 are to be drawn so that, for each square, one vertex is on circle C and the rest of teh square is inside circle C. What is the greatest number of such squares that can be drawn if the squares do not have overlapping areas?</li>
</ol>
<p>a. none
b. one
c. two
d. three
e. four</p>
<p>I know this might be hard to explain online, but geometry a major weak spot for me. So, if you could try, I’d really appreciate it.</p>
<li>In a plane, lines are drawn through a given point O so that the measure of each non-overlapping angle formed about point O is 60 degrees. How many different lines are there?</li>
</ol>
<ol>
<li><p>Sqrt2, what's so special about the number? It is the length of the diagonal of a unit square! Given this, draw a circle. Then draw two diameters in the circle so that they are perpendicular to each other. You will be able to see that you can draw four squares with diagonals sqrt2 that do not overlap each other. Therefore, the answer is e. </p></li>
<li><p>How many 60 degrees are in 360? 6! How many lines does it take to create 6 equal angles that form 360? 3! Therefore, the answer is b.</p></li>
</ol>
<p>I totally did not remember that the length of a diagonal of a unit square is sqrt2. I told you I was a big doof w/ math. </p>
<p>For the other question, I thought the answer was b but I was trying to follow that one trick where they say a hard question has a hard answer. I guess I was just assuming since the question was last it'd be hard so i convinced myself that b couldn't be the answer since it did seem pretty simple. Ahh..</p>