<p>Sorry if I wasn’t clear.</p>
<p>I meant that you said in your last post that a singular noun (“Like the area”) suggests a singular comparison (“the Western Basins and Plateau region”), so “offer” would be incorrect. So would this mean that by saying “Like Jim” (implying a singular noun), “Jack and Jill” would be incorrect since its plural?</p>
<p>“I see your point. But which sentence do you mean by “that sentence”? The Jack and Jill one, or the one about the Plateau?”</p>
<p>The Jack and Jill one, my bad.</p>
<p>
</p>
<p>That’s an excellent question, and the answer is no, because “Jack and Jill” aren’t functioning as adjectives.</p>
<p>Thanks! I guess it’s too late and irrelevant to think about it now, anyway. But I do have another question (not hard, lol)</p>
<p>Do you have underline book titles and use quotation marks while writing the essay?</p>
<p>^Yes, underlining book titles is standard. Poems and short works go in quotation marks. Good luck on the essay :).</p>
<p>Dear diary:</p>
<p>I’m wrapping up work on a few recondite math problems. I hope to go to sleep early. Good luck EVERYONE :D. PS: I find it funny how people across the world are taking the SAT as I sleep :p. </p>
<p>GOOD LUCK EVERYONE!</p>
<p>IceQube</p>
<p>Hey, IceQube, can you please share some of these abstruse, obscure, recondite, covert, esoteric math problems with us?</p>
<p>Hey, everyone on this thread, best of luck (: </p>
<p>I’m going to miss this study thread :c</p>
<p>After tomorrow, is everyone going to stop updating this thread??? NOOO…I’m going to to be depressed :(</p>
<p>BTW, everyone, GOOD LUCK!!! I HOPE ALL OF YOU DO VERY VERY WELL!!! I’LL KEEP ALL OF YOU IN MY PRAYERS :)</p>
<p>Can someone explain this please?</p>
<p>In a bag that contains 28 marbles that are either red or blue, the ratio of the number of red marbles to the number of blue marbles is 5:2. If 4 blue marbles are added to the bag, How many red marbles should be added to maintain the 5:2 ratio?</p>
<p>In a bag that contains 28 marbles that are either red or blue, the ratio of the number of red marbles to the number of blue marbles is 5:2. If 4 blue marbles are added to the bag, How many red marbles should be added to maintain the 5:2 ratio?</p>
<p>The bag has 20 red marbles and 8 blue marbles. (Note that this would be impossible if 28 was not a multiple of 7 or (5+2))</p>
<p>If you add 4 blue marbles to the bag, you now have 12 blue marbles. In order to balance the 12 blue marbles you need to have (12*5/2) or 30 marbles.</p>
<p>Let’s check our work: 30:12 = 5:2.</p>
<p>Now we subtract the initial amount of red marbles from the total as follows: 30 - 20.</p>
<p>The answer is 10. You must add 10 marbles to maintain the ratio.</p>
<p>There are 28 marbles.
Red : Blue = 5:2</p>
<p>20 red 8 blue; add 4 blue marbles
20 red 12 blue; The ratio is 5:3</p>
<p>You need to add an x number of red marbles to maintain a 5:2 ratio.</p>
<p>(20+x)/12 = 5/2; cross multiply
60 = 2(20+x);
60 = 40+2x;
20 = 2x;
x = 10</p>
<p>OR</p>
<p>5/2 = x/4
x = 10</p>
<p>Thanks – I get it now. Well, I wish everyone luck and hope you all get a good nights rest. I’m going to go to bed at 10 and get up at 6:30 so I’ll get an good nights rest. I’m
shooting for:</p>
<p>CR: 800
M: 750
W: 800</p>
<p>I know i can do it. Everyone try to remember as many questions as you can too! Good luck and goodnight.</p>
<p>Hey Jeffrey, I have a challenge for you!</p>
<p>For some positive real number a, the first 3 terms of a geometric progression are a 1, a + 3 and 3a + 1. What is the numerical value of the fourth term?</p>
<p>(a) 25
(b) 36
(c) 32
(d) 100
(e) 9</p>
<p>Anyway, I’m hoping for 800 math tomorrow. Solid CR (mid 700s would be quite satisfactory). And, I’m confident enough that I’ll do fine on Writing MC so I don’t have a particular goal–an 11 or 12 essay would be nice, to give me a bit of leeway.</p>
<p>
</p>
<p>The answer is C, 32. Not sure of the best way to solve it but guess and check works fine since a has to be a small digit because of the low answer choices.</p>
<p>Darn it! I should have checked CC a month before the test, instead of the night before!</p>
<p>This thread looks amazing on the surface, and the people here seem very intelligent. I’m sure you’ll all do fine. Good luck tomorrow!</p>
<p>a – 1, a + 3 and 3a + 1</p>
<p>a+3 = b(a-1)
3a+1 = b(a+3);
b = (3a+1)/(a+3);</p>
<p>a+3 = (a-1)(3a+1)/(a+3);
(a+3)(a+3) = (a-1)(3a+1);
a²+6a+9 = 3a² - 2a - 1;
0 = 2a² - 8a - 10;
0 = 2(a²-4a-5);
0 = 2(a-5)(a+1);
a = 5 and -1, but since a must be positive, a = 5.</p>
<p>a+3 = b(a-1);
5+3 = b(5-1);
8 = 4b;
b = 2;</p>
<p>(3a+1)(b) = the fourth term
(3<em>5+1)(2);
16</em>2 = 32</p>
<p>The fourth term is 32…</p>
<p>Good luck all! What really sucks is my midterms were this week. I had practically NO time to study…■■■</p>
<p>I think the parabola question is quite hard in SAT sense, as I utilized differentiation and sum of roots of quadratic equation which I never expected to use in SAT I.</p>
<p>@warsovereign
I think you can use the fact that the parabola is symmetrical, as the vertex is given.</p>
<p>@lwxted
Yeah, my brain was haphazard at that moment.
My testing center was too stifling in atmosphere and couldn’t leave me to think calmly.
What I did was to get x-coordinate of the vertex -b/2a=2, and then sum of root -b/a=4, so the third point is x=7.</p>