<p>Solve for Q</p>
<p>p = 2/(m+q)</p>
<p>Could you explain please... I really don't know why I'm still struggling with this. Thanks.</p>
<p>Ok I think I it should be p(m+q) = 2</p>
<p>Then distribute pm+pq=2</p>
<p>then subtract pm, pq=2-pm </p>
<p>then divide by p, q=(2-pm)/p</p>
<p>I really had to think about this problem. Is there a good internet site or book that will help me grasp these simple concepts I seem to be having problems with?</p>
<p>p = 2/(m+q)</p>
<p>p(m+q) = 2
m + q = 2/p
q = 2/p - m</p>
<p>The book says the answer is q=(2-pm)/p</p>
<p>I checked and the equation is stated correctly. </p>
<p>Is the books answer incorrect for the original given problem?</p>
<p>Could both answers be correct?</p>
<p>(2-p*m)/p=2/p-m</p>
<p>q=(2-pm)/p
when you simplify this further, it becomes q = 2/p - pm/p
which simplifies to q = 2/p - m</p>
<p>Both answers are correct but mine is just one step further.</p>
<p>The book probably wants the answer as a common fraction with common denominators</p>
<p>Thanks, I skipped the first two chapters of the book and tried to just do a few examples but I haven’t taken algebra in 3 years so I went back and read through the chapters. I think I got it now, I’m now moving onto polynomials. Trying to get into and finish college agebra and trig before school so I can take calc 1.</p>