NEED HELP! math problem!

<p>Hey,</p>

<p>I need help on problem number 26 on Math Level 2 from the Subject Test Preparation Booklet:</p>

<p><a href="http://www.collegeboard.com/prod_downloads/prof/counselors/tests/sat/2006-07-SAT-subject-tests-preparation-booklet.pdf%5B/url%5D"&gt;http://www.collegeboard.com/prod_downloads/prof/counselors/tests/sat/2006-07-SAT-subject-tests-preparation-booklet.pdf&lt;/a&gt;&lt;/p>

<p>Can anyone figure this problem out? Thanks!</p>

<p>Let X = the center of the circle.</p>

<p>Angle CAX and CBX = 90. (They are tangent to the circle)</p>

<p>So angle AXB = 360 - 50 - 90 - 90 = 130.</p>

<p>Now you have an isosceles triangle with sides 2, 2, and AB. The angle between the sides of length 2 is 130. Use the law of cosines to solve for AB.</p>

<p>AB^2 = 2^2 + 2^2 - (2)(2)(2)(cos130)
AB = 3.63</p>

<p>Thanks! That one was a real stumper for me.</p>