<p>Hey,</p>
<p>I need help on problem number 26 on Math Level 2 from the Subject Test Preparation Booklet:</p>
<p>Can anyone figure this problem out? Thanks!</p>
<p>Hey,</p>
<p>I need help on problem number 26 on Math Level 2 from the Subject Test Preparation Booklet:</p>
<p>Can anyone figure this problem out? Thanks!</p>
<p>Let X = the center of the circle.</p>
<p>Angle CAX and CBX = 90. (They are tangent to the circle)</p>
<p>So angle AXB = 360 - 50 - 90 - 90 = 130.</p>
<p>Now you have an isosceles triangle with sides 2, 2, and AB. The angle between the sides of length 2 is 130. Use the law of cosines to solve for AB.</p>
<p>AB^2 = 2^2 + 2^2 - (2)(2)(2)(cos130)
AB = 3.63</p>
<p>Thanks! That one was a real stumper for me.</p>