<p>the Equation
A=C(1+r/100)^n
9540=15000(1+r/100)^3</p>
<p>How do i use logs to solve this problem
cant remember logs.....i learned it in the stone age</p>
<p>9540=15000(1+r/100)^3</p>
<p>why use logs? set u=1+r/100 and then solve for u...then solve for r. Not so bad.</p>
<p>can you show me how to do that......not really sure what you mean</p>
<p>bumpppppppppp......need help....test tomorrow</p>
<p>A=C(1+r/100)^n
9540=15000(1+r/100)^3</p>
<p>If u=1+r/100, then</p>
<p>9540=15000u^3
.636=u^3
u = .. . . . something, don't want to get my calc</p>
<p>so . . set whatever you get for u equal to
1+r
100</p>
<p>and solve for r</p>
<p>i did that but somehow i am getting 20% and 14 %
and i forgot to mention one thing.....its a depreciaation problem.....so it shouldnt be 1-r/100</p>