Need help with Calc AB FRQ 2006 Q5

<p>In the solution's guide why are they able to get rid of the absolute value sign and where do they come up with the equations at the end and why is the domain X<0</p>

<p>any help is appreciated!! here is the link to the question…its is number 5</p>

<p>BUMP! Can anyone provide a link explaining these dots and slopes on the graph? </p>

<p>I wasn’t paying attention when my teacher went through them…</p>

<p><a href=“College Board - SAT, AP, College Search and Admission Tools”>College Board - SAT, AP, College Search and Admission Tools;

<p>you plug in a point…say (1,1) into the dy/dx equation…1 for y and 1 for x…whatever dy/dx equals at that point is the slope which you draw on the slope field…you gota do it for all the points
anyone can help with orginal question?</p>

<p>Where is the link? Did it get removed?</p>

<p>samd - if im not mistaken you loose absvalue because if you work out both the + and - you get the same thing</p>

<p>Taking off the absolute value sign is not necessary but results from the fact that the domain of the function is all negative numbers so absolute value of x is the same as -x. The domain comes from the fact that the derivative is undefined at x=0. So your new domain must include the given point (at x=-1) but can’t jump over the discontinuity giving a domain of (0, infinity) or x<0</p>

<p>awwww ok thank you so much kwwboarder…hoping for a slope field problem tomoro:)</p>

<p>no problem, explaining things to other people helps me study so it’s win-win :)</p>