<ol>
<li>Carol has twice as many books as Beverly has. After Carol gives Beverly 5 books, she still has 10 more books than Beverly has. How many books did Carol have originally?</li>
</ol>
<p>A.) 20 B.) 25 C.) 30 D.) 35 E.) 40</p>
<p>I keep on getting C (30). I did C=2B. C-5=B+10. B=c/2. C-5=C/2 + 10. C/2=15 C=30.
but the answer keep on saying its 40 (E) which doesn't make any sense.</p>
<ol>
<li>If s equals (1/2) percent of t, what percent of s is t?</li>
</ol>
<p>A.) 2% B.) 200% C.) 2000% D.) 20,000% E.) 200,000%</p>
<p>Anyone know how to answer this type of question? (number 2).
Answers D.</p>
<p>Thanks!</p>
<ol>
<li>Carol has twice as many books as Beverly has. After Carol gives Beverly 5 books, she still has 10 more books than Beverly has. How many books did Carol have originally?</li>
</ol>
<p>C=2B
C-5=B+10 so C=B+15 which also equals (from above) 2B.
2B=B+15 or B=15 and C (which equals 2B)=30</p>
<ol>
<li>If s equals (1/2) percent of t, what percent of s is t?</li>
</ol>
<p>s=.005<em>t … note that .005 is 1/2 percent.
t=200</em>s (divide both sides above by .005, and note that 1/.005=200). Convert “200” to percent. Well “1” is 100%, so 200 is 20000%</p>
<p>My solution above of (1) is incorrect. The post on the SAT forum has the correct analysis.</p>
<p>C=2B
C-5=(B+5)+10 so C=B+20 which also equals (from above) 2B.
2B=B+20 or B=20 and C (which equals 2B)=40</p>
<p>For 1) you have to remember that Carol GIVES 5 books, and Beverly RECIEVES 5 books. That’s why it’s C-5=B+5+10</p>