<p>(a-b)^n = (b-a)^n </p>
<p>If n is an integer from 100 to 110, inclusive, and the equation above is true for all numbers a and b, how many different values of n are possible?</p>
<p>PLease answer!</p>
<p>n must be even, as (b-a)^n = (a-b)^n * (-1)^n, so we want (-1)^n = 1. The answer is 6.</p>
<p>This question is more appropriate for the SAT forum, not the AP forum.</p>