<h1>1 The average (arithmetic mean) of the test scores of a class op students is 70, and the average of the test of a class of n students is 92. When the scores of both classes are combined the average score is 86. What is the value of p/n?</h1>
<p>6/16 </p>
<p>10char</p>
<p>To have an average come out to a particular value, the “overs” have to balance with the “unders”. For example, 88 and 92 balance to an average of 90. But if you had two 88’s, you’d need a 94 to balance out the average to a 90.</p>
<p>So in this problem, there are 70’s and 92’s that somehow balance to an 86. The 70’s are each 16 “under” and there are p of them. The 92’s are 6 “over” and there are n of them. But they balance – so 16p = 6n .</p>
<p>Then divide both sides to get p/n = 6/16.</p>
<p>I believe simple algebra is best for this problem.
(70p+92n)/(p+n)=86
70p+92n=86p+86n
6p=16n
p/n=16/6</p>
<p>^gertrudetrumpet you mixed up the p and n values in your equation; it should be 6n = 16p or vice versa. Nevertheless, I like your explanation the best.</p>
<p>pckeller you had a good explanation as well.</p>