<p>If /x-3/ > 3, which of the following could be a value of x?</p>
<p>A -1
B 0
C 2
D 3
E 6</p>
<p>BTW.....those slashes are supposed to be absolute value signs....</p>
<p>If (x+y)^2 - (x-y)^2 = 84 and x and y are positive integers, which of the following could be a value of x + y?</p>
<p>A 10
B 12
C 14
D 16
E 18</p>
<p>Thanks you guys!</p>
<p>Haha questions from the psat review booket? Yeah I just did that today too.</p>
<p>First question-
|x-3|>3
x-3>3 or x-3<-3 You have to set up 2 equations because it's absolute value. Of of them is the same as the original, the second one, you flip the <> sign and insert a negative in front of the answer.
Once you solve that you'll get X>6 or X<0 so the answer is A) -1</p>
<p>Second question-
Factor it out. You'll get
(X^2+2xy+y^2) - (X^2-2xy+y^2) = 84 Distribute the - and solve. You'll get
4xy = 84
xy=12 (B)</p>
<p>Good luck.</p>
<p>Thank you so much Rainmaker! Just a little correction though, according to the answer sheet the answer to the second one is A. I think because 4xy = 84, and after dividing both sides by 4, xy = 21. Therefore the answer is 10 since x and y could be equal to 3 and 7 since 3 x 7 = 21 and 3 + 7 = 10, which is one of the answers. Haha, I'm sure you already knew all this, but I just wanted to clarify.</p>
<p>With that being said, could you, or anybody else with the PSAT booklet help me numbers 4 and 20 in section two?</p>
<p>nvm just found this awesome link that someone posted here!</p>
<p>Ok, what in the world is up with the explanation for #20 on section 2?</p>
<p>I'd copy and paste the explanation but it comes out weird. Can someone look at it in the link above?</p>
<p>In the second to last sentence, how in the world did that simplify?</p>
<p>6r+18 = xr
18= r(x-6)</p>
<p>I'm getting frustrated. How in the world is 6/r = x/(r + 3) equal to 6r + 18/r??????</p>
<p>cross multiply...
you get 6r+18 = rx
now divide r to both sides..</p>
<p>x= 6+ 18/r</p>