<p>If k, n, and x are positive numbers satisfying x^-4/3=k^-2 and y^4/3=n^2 , what is (xy)^-2/3 in terms of n and k</p>
<p>answer is k/n</p>
<p>I think the answer is (kn)^-1.</p>
<p>wats the CORRECT answer? like greennblue I am getting (kn)^-1</p>
<p>Write your exponents properly please</p>
<p>If k, n, and x are positive numbers satisfying x^(-4/3)=k^(-2) and y^(4/3)=n^2 , what is (xy)^(-2/3) in terms of n and k</p>
<p>(xy)^(-2/3)
= x^(-2/3) y^(-2/3)</p>
<p>Now we need to manipulate our other two equations
x^(-4/3) = k^(-2) and raise each side to the 1/2 power
x^(-2/3) = k^(-1)</p>
<p>y^(4/3) = n^2 raise both sides to -1/2 power
y^(-2/3) = n^(-1)</p>
<p>(xy)^(-2/3)
= x^(-2/3) y^(-2/3)
= k^(-1) n^(-1)
= 1/(kn)</p>
<p>Either you wrote the problem or the answer wrong.</p>
<p>How did you figure that out? How did you know to raise by 1/2…would’ve never got the answer to this one…</p>