<ol>
<li>The sum of an infinite geometric series with the first term A and a common ratio,1 is given by A/1-r. The sum of a given infinite geometric series is 200, and the common ratio is 0.15. What is the second term of this series?</li>
</ol>
<p>The other ones I need help with are numbers, 48. 49, 50, and 53 but they are too hard to post. </p>
<p>I really need help! thanks</p>
<p>heres the link for the test:</p>
<p><a href="http://www.act.org/aap/pdf/preparing.pdf%5B/url%5D">http://www.act.org/aap/pdf/preparing.pdf</a></p>
<h1>60 is very easy.</h1>
<p>You just plug in r and the SUM into the formula given and you get an (a) value. That value is your first term. Since the common ratio is 0.15, you just multiply 0.15 by the (a) value to get the second term. (REMEMBER THIS IS A GEOMETRIC SEQUENCE SO YOU MULTIPLY THE PRECEDING TERM BY THE COMMON RATIO TO GET THE NEXT TERM)</p>
<p>ok, i feel stupid now. I think I just let the words confuse me. </p>
<p>can you do the others by any chance? thanks!</p>
<p>For #48, it’s pure logic. If the complex numbers graphed in the complex plane are comparable to (a,b) on a standard coordinate plane, and the modulus of those complex numbers is determined by sq.rt(a^2 + b^2), then you look for the complex numbers would have the highest (a,b) value. Only z1 would fit because it is furthest from the real axis and the imaginary axis. I hope that made sense but just think of each point on the graph as plotted (a,b). The question is asking, essentially, which point on the graph would make the the said equation the highest value?</p>
<p>For #49, you’re going to have to use your algebra skills. If the equation is 8^(2x+1)= 4^(1-x), then you can simplify both sides by using two as the factor of 8 and 4 respectively. So the simplified equation becomes 2^(3 * (2x+1))= 2^ (2* (1-x))</p>
<p>If you have no idea what i did there, you need to re-review algebra.
Since both sides of the equation have the same base, 2, you can just make a new equation by using the exponents.
So the new equation would be: 3 * (2x+1)= 2 * (1-x)
Simplified, it’s 6x +3= 2-2x
Solve for x, which comes out to be -1/8. Answer Choice (C)</p>
<h1>50 is knowledge based type of problem. All you have to do is think to yourself “this graph is symmetrical to the y-axis” In other words, the graph is even or choice F.</h1>
<p>The graph can’t be odd because odd graphs are one that are symmetrical to the origin so choice G is out. It can’t be H, J or K because they don’t make sense.</p>
<h1>53 is also another knowledge based problem. You’re going to have to know what a cosine is. Cosine= adjacent/hypotenuse. So tan^-1(a/b) is the ANGLE MEASURE between side b and SQ RT (a^2 + b^2). All you have to do is find the cosine measure of that angle; in other words, the cosine measure is adjacent/hypotenuse or b/sq.rt (a^2 + b^2), answer choice D.</h1>
<p>Hope i helped. Lemme know if you need mo clarification aiight?</p>
<p>Aight son imma bounce. Holla at me if you need mo help</p>