<p>Bah. Most of the test was doable, but I skipped some questions apparently simple questions out of uncharacteristic nervousness. I’ll won’t score 800 and I’ll be lucky to hit at least 750. Stupid “standardized” testing.</p>
<p>Yeah. It’s a shame our lives revolve around bubbling in circles lol.</p>
<p>nig- im referring to the 1 where it was an isosceles with base 5 while the sides were 10.</p>
<p>You do not need two angles for the law of cosines. How is (0,0) intersecting the y-axis since it is not in the third or fourth quadrant? Or is it in those quadrants?</p>
<p>Yeah, the nerves really got to me for this test… Usually I don’t miss any questions and finish with a few minutes to go. This time I skipped 3 and was pressed for time! I just hope I’ve made very few silly mistakes. I already know I misread one question on top of the 3 omits, so 1 more and I’m probably around the boundary for an 800. It’s getting pretty tight…</p>
<p>Did anyone get an answer that was like the domain is all real numbers?</p>
<p>Oh, then yeah. They want you to use Law of Cosines on that one. </p>
<p>c^2 = (a^2 + b^2)-2abcos(C)
where c=6, a =10, and b=10 as well.</p>
<p>X^2 / X^2 + 1</p>
<p>I said domain was between 0<= x < 1 …</p>
<p>Not two angles, i mean 3 sides and an angle, or atleast a method to get to that.</p>
<p>i got all real for domain</p>
<p>Domain for that one is all real numbers. Domain constitutes all numbers that x can be. X can be everything except where it would make the denominator 0. In this case, x^2+1 will never equal zero for any real value of x, and therefore the domain is all real numbers.</p>
<p>well how can x^2 / x^2 + 1 equal any number greater than one?</p>
<p>Unless we are talking about different questions…</p>
<p>Edit: Nvm, I see. I got it wrong.</p>
<p>thequestionmark - domain is the values of which x can be. you’re thinking of range and limits.</p>
<p>@thequestion</p>
<p>why only between 0 and 1?</p>
<p>I put all reals too</p>
<p>For the non-congruent triangles one, shouldn’t the answer be two? Since you’re given the SSA, and that follows the ambiguous case. Or did I read something wrong?</p>
<p>What did you guys get as the limit as x tended to 1.5 for that function? (can’t remember what the function was but it involved a fraction with (2x+1), (2x-1) and (x+1))</p>
<p>okay. angle A is 42. AB is 6 and BC is 4.</p>
<p>So let’s say AC is horizontal. Then AB would be length 6 at a 42 degree angle above the horizontal. Then, BC would have to go from point B to the horizontal line (containing point C). The shortest possible distane from B to the horizontal line is the distance that creates a right angle with AC. This distance BC is 4.02 (by law of sines) which is greater than 4. Therefore BC can never touch line AC and no triangles can be formed.</p>
<p>
</p>
<p>-6 I believe.</p>
<p>^ This. Or if you invoke the law of sines and use your calc, you’ll get something like sinx= 1.003. Not possible, et viola.</p>
<p>Hmm. The answer to the functions one was something like 2.5/6 (simplified?)</p>
<p>Anyone remember</p>
<p>z = i - 1
z^2 = 2i?</p>
<p>The point was just -2 on the graph?</p>